I have no hard evidence of this so take it worth a grain of salt, but it would be more consistent with your suggested definition.\) miles. There is one quotation from there that suggests to me the original meaning of polynomial may have been: Any string of mathematical expressions connected by addition and subtraction. There is a brief investigation of the origin of the word "Polynomial" here : Link Then when the student is comfortable with polynomials adding the more complicated negative powers is just an easy modification of what has already been learned. Polynomials are probably the most well behaved functions there are (no singularities, continuous and differentiable everywhere, etc.) it is helpful to study them separately first. There are a lot of rules that apply to the polynomial family as a whole which you would lose if you included negative powers into the definition. There are good pedagogical reasons to teach polynomials with just positive powers. Laurent Series), but then you just wouldn't call it a polynomial. Practically speaking you frequently want to work with negative powers of $x$ as well as positive powers (e.g. Polynomial is just a name for a certain kind of structure. Numerators and denominators are the key ingredients that make fractions. I don't know if there is a "good" reason. Knowing how to get rid of negative exponents is key to fully simplifying an. In other words, negative exponents in the numerator can be written as positive exponents in the denominator, and negative exponents in the denominator can be. There are, indeed, other algebraic structures that allow the evaluation functions to constants, but the ring of real polynomials $R$ is the only one that allows the variable $x$ to be evaluated to an element of any larger structure containing $\mathbb R$ (to any $R$-algebra). I stress that the domain is the set of polynomials, and the target space, also known as codomain, is $\mathbb R$ (the algebra $A$ in the general case). Rewrite the expression by moving the factor with a negative exponent to th. The function $e_a$ may be called the evaluation morphism. How to simplify an algebraic fraction with a negative exponent in the denominator. That is, it satisfies $e_a(f+g)=e_a(f)+e_a(g)$ and $e_a(fg)=e_a(f)e_a(g)$, as well as $e_a(\mathbf1)=1$, where the bold-face $\mathbf1$ is the constant polynomial $1$, and the other $1$ is the ordinary unit element of $\mathbb R$. And this function is both additive and multiplicative (it’s a ring morphism from $R$ to $A$). That is, once you’ve chosen $a$, then $f(a)$ makes sense as a real number (as an element of $A$) no matter what polynomial $\,f$ you look at.įurthermore, the choice of $a$, once it’s done, gives you a function from polynomials to constants, I’ll call it $e_a$, namely $e_a(f)=f(a)$. Just to speak only of polynomials in one variable, the set of all such, $\mathbb R$ ($R$ for a general ring), has the property that the variable $x$ may be evaluated to any real number $a$ (to any element $\alpha$ of an algebra $A$ over the base ring $R$) so that this “evaluation mapping” can be applied to any polynomial at all (to any element of $R$ at all). The set (ring, actually) of polynomials with real coefficients (more generally with coefficients in any commutative ring) has a “universal” property that the larger sets do not. This is illus-trated in the following example. This nal result is an imporant property known as the zero power rule of expo-nents Zero Power Rule of Exponents:a0 1 Any number or expression raised to the zero power will alwaysbe 1. I’ll try to make my explanation as elementary as I can, with parenthetical expansions for the more technically inclined. When we want to simplify with negative exponents, we take the reciprocal of the base and make the exponent positive. aaa aaa Reduce out all theas 1 Our Solution,when we combine the two solutions we get: 1 a0 Our nal result. Here’s my understanding of the reason for the restrictiveness of the definition of “polynomial”, in response to suggestion. I would opine that the reason that they're not the primary object of study is because they're not the 'simplest' structure of interest among any of their peers, and fundamentally the most important structures in mathematics tend to be the simplest structures exhibiting some given property. Redden 11.1K subscribers Subscribe Share 19K views 10 years ago Negative Exponents How to work with negative exponents in an algebraic fraction. As that article suggests, they're of particular importance and interest for their connections with the field of Hopf Algebras (and by extension, quantum groups). What's more, there's also an object occasionally studied that more directly corresponds to your notion: the notion of Laurent Polynomial. Polynomials are defined as they are for a few distinct reasons: (1) because polynomials as functions have certain properties that your 'polynomials with division' don't have, and (2) because there are other terms for more generalized algebraic forms.įirst, the properties of polynomials: unlike e.g., $2x^$.
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